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"The active force in the Absolute represents the maximum 'density of vibrations,' while the matter in which these vibrations proceed, that is, the first 'carbon,' represents the minimum density of matter.

"The note si in the Absolute will be the conductor of the passive force designated by the number 2. And the matter in which this passive force acts or in which sounds the note si will be 'oxygen' (0).

"The note la will be the conductor of the neutralizing force designated by the number 3, and the matter in which sounds the note la will be 'nitrogen' (N).

"In the order of the action of the forces they will stand in the succession 1, 2, 3, that is, corresponding to the matters 'carbon,' 'oxygen,' 'nitrogen.' But by density of matter they will stand in the order: 'carbon,' 'nitrogen,' 'oxygen,' that is, 1, 3, 2, because 'nitrogen' by retaining the number 3, that is to say, by being the conductor of the neutralizing force, stands by its density of matter between 'carbon' and 'oxygen,' and 'oxygen' appears as the densest of the three.

H6

"'Carbon,' 'oxygen,' and 'nitrogen' together will give matter of the fourth order, or 'hydrogen' (H), whose density we will designate by the number 6 (as the sum of 1, 2, 3), that is, H6:

The first triad

do С 1 1 1 si О 2 3 2 la N 3 2 3

"C, O, N retain their numbers 1, 2, 3. 'Carbon' is always 1, 'oxygen' is always 2, and 'nitrogen' is always 3.

"But being more active than 'oxygen' 'nitrogen' enters as the active principle in the next triad and enters with the density of 2. In other words 'nitrogen' has a density of 2 and 'oxygen' a density of 3.

"So that the note la of the first triad is the conductor of the active force in the next triad which it enters with the density of 2. If 'carbon' enters with the density of 2, then 'oxygen' and 'nitrogen' must correspond to it in densities, repeating the ratio of densities of the first triad. In the first triad the ratio of densities was 1, 2, 3; in the second triad it should be 2, 4, 6, that is, 'carbon' of the second triad will possess the density of 2, 'nitrogen' a density of 4, 'oxygen' a density of 6. Taken together they will give 'hydrogen' 12 (H12):

The second triad

"According to the same plan and order the following triad will be constructed: fa, 'shock,' mi. 'Carbon' which was 'nitrogen' in the second triad enters with a density of 4; the 'nitrogen' and 'oxygen' corresponding to it must have a density of 8 and 12; together they will give 'hydrogen' 24 (H24):

The third triad

"The next triad mi, re, do, by the same plan and order will give 'hydrogen' 48 (H48):

The fourth triad

"The triad do, si, la will give 'hydrogen' 96 (H96):

The fifth triad

the triad la, sol, fa—'hydrogen' 192 (H192): The sixth triad

la С 32 32 32

sol О 64 96 64 H192

fa N 96 64 96

fa, 'shock,' mi-'hydrogen' 384 (H384):

The seventh triad

64 64

192 128 H384

192 128 192

H768

mi, re, do—'hydrogen' 768 (H768): The eighth triad

mi С 128 128 128 те О 256 384 256 do N 384 256 384

do, si, la—'hydrogen' 1536 (H1536): The ninth triad

do С 256 256 256

si О 512 768 512 H1536

la N 768 512 768

fa С 64 — О 128 mi N

la, sol, fa—'hydrogen' 3072 (H3072): The tenth triad

H3072
5x2
1536 1024
la С sol О fa N
512
1024 1536
512 1024 1536

fa, 'shock,' mi—'hydrogen' 6144 (H6144): The eleventh triad

1024 2048 3072
H6144

fa С 1024 1024 — О 2048 3072 mi N 3072 2048

mi, re, do—'hydrogen' 12288 (H12288):

The twelfth triad

re О 4096 6144 4096 H12288

"Twelve 'hydrogens' are obtained with densities ranging from 6 to 12288. (See Table 1.)

"These twelve 'hydrogens' represent twelve categories of matter contained in the universe from the Absolute to the moon, and if it were possible to establish exactly which of these matters constitute man's organism and act in it, this alone would determine what place man occupies in the world.

do С 1 X г do"
si О 2 3 2 Лб si ► H6
la N 3 2 3. С 2 2 2' la .
sol О 4 6 4 -Hi 2 sol -Hia
fa С 4 4 4 N 6 4 6, fa'
О 8 12 8 »На4 -H24
mi N 12 8 .J С 8 8 8' mi.
re О 16 24 16 -Н48 re -H48
do С 16 16 i6- N 24 16 24- do'
si О З2 48 З2 ►Н96 si ■H96
la N 48 3* 48 С З2 З2 З2" la .
sol О б4 9б 64 - Н192 sol •H193
fa С 64 64 64 N 96 64 96 fa"
О 128 192 128 'Н384 H384
mi N i9a 128 192, С 128 128 128- mi.
rc О 256 384 256 .Н768 re -H768
do С 256 256 25fr N 384 256 384. do"
si О 512 768 ►Нх53б si Н1536
la N 768 512 С 512 512 512 la.
sol о 1024 1536 1024 -Н3072 sol -H3072
fa С 1024 1024 1024" N 1536 1024 *536, fa'
О 2048 3°72 2048 -Н6144. H6144
mi N 3072 2048 3°72. С 2048 2048 2048" mi
re о 4096 6144 4096 -Н13288 re •H1328I
do N 6144 Table 4096 1 6144. do